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1 The distance formula will be used to find the distance from the center to one of the points on the circle This will yield the radius d = √(x2 − x1)2 (y2 − y1)2 d = √(7 − 3)2 (2 − ( − 1))2 d = 221 #2 Substitue y=mx4 into the circle equation x^2 (mx4)^2 = 2 (mx4) Find all m that gives exactly 1 solution for x You can use completing the square for x to X^2+y^2=1 unit circle

The order of the differential equation whose solution is `x^ (2)y^ (2)2gx2fyc=0` is Sarthaks eConnect Largest Online Education CommunityThe equation x2 y2 2gx 2fy c = 0 always represents a circle whose centre is (g, f), that is ( 1 2 coefficient of x, 1 2 coefficient of y) and radius is g 2 f 2 − c If g2 f2 c = 0 then theLet C_1x^2y^22gx2fyc=0 and C_2=x^2y^22gx2fyc_1=0 Now note that C_1=(xg)^2(yf)^2=f^2g^2c and C_2=(xg)^2(yf)^2=f^2g^2c_1 Now assuming that Why The Equation Of Circle Is X 2 Y 2 2gx 2fy C 0 Where Did This Equation Came From Quora X^2+y^2+2gx+2fy+c=0 differential equation